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better fix

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This commit is contained in:
Marc Delisle
2002-08-09 13:01:24 +00:00
parent d4ad527766
commit 58bb4d5c78
2 changed files with 6 additions and 5 deletions
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3
ChangeLog
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@@ -6,7 +6,8 @@ $Id$
$Source$ $Source$
2002-08-09 Marc Delisle <lem9@users.sourceforge.net> 2002-08-09 Marc Delisle <lem9@users.sourceforge.net>
* user_details.php3: bug 591602, mysql.user lowercase "password" * user_details.php3: bug 591602, mysql.user lowercase "password",
thanks to Thomas B<>hr <baehr at glaswald.de>
* lang/romanian: update, thanks to Valics Lehel * lang/romanian: update, thanks to Valics Lehel
2002-08-09 Robin Johnson <robbat2@users.sourceforge.net> 2002-08-09 Robin Johnson <robbat2@users.sourceforge.net>

8
user_details.php3
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@@ -997,11 +997,11 @@ if (PMA_mysql_error()) {
//$result = @PMA_mysql_query('SELECT COUNT(Password) FROM mysql.user'); //$result = @PMA_mysql_query('SELECT COUNT(Password) FROM mysql.user');
//$password_field = (($result && PMA_mysql_result($result, 0)) ? 'Password' : 'password'); //$password_field = (($result && PMA_mysql_result($result, 0)) ? 'Password' : 'password');
$result = @PMA_mysql_query('Select * from user limit 1'); // using a syntax that works with older and recent MySQL,
// and assumes that the field name ends with "assword":
$result = @PMA_mysql_query('SHOW FIELDS FROM user FROM mysql LIKE \'%assword\'');
if ($result) { if ($result) {
// assumes that the password is always the third field of mysql.user $password_field = PMA_mysql_result($result, 0);
$field_info = PMA_mysql_fetch_field($result,2);
$password_field = $field_info->name;
} }
/** /**