Render just the B field: it gives a better visualization here
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@@ -8,7 +8,10 @@ fn main() {
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let mut step = 0u64;
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loop {
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step += 1;
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state.impulse_ey(50, 50, 50f32 * ((step as f64)*0.1f64).sin() as f32);
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let imp = 50.0 * ((step as f64)*0.05).sin() as f32;
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state.impulse_ex(50, 50, imp);
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state.impulse_ey(50, 50, imp);
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//state.impulse_bz(50, 50, imp / 3e8f32);
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Renderer.render(&state);
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state.step();
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thread::sleep(time::Duration::from_millis(33));
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@@ -33,6 +33,15 @@ fn norm_color(v: f32) -> u8 {
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(v * 64.0 + 128.0).max(0f32).min(255f32) as u8
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}
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fn curl(x: f32, y: f32) -> f32 {
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let c = x * y;
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if c >= 0f32 {
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c.sqrt()
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} else {
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-(-c).sqrt()
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}
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}
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impl ColorTermRenderer {
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pub fn render(&self, state: &SimState) {
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let mut buf = String::new();
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@@ -42,8 +51,11 @@ impl ColorTermRenderer {
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let cell = state.get(x, y);
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//let r = norm_color(cell.bz() * consts::C);
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let r = 0;
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let g = norm_color(cell.ex());
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let b = norm_color(cell.ey());
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let b = 0;
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//let g = norm_color(cell.ex());
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//let b = norm_color(cell.ey());
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//let g = norm_color(curl(cell.ex(), cell.ey()));
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let g = norm_color(cell.bz() * 3.0e8);
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write!(&mut buf, "{}", RGB(r, g, b).paint(square));
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}
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write!(&mut buf, "\n");
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